Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)=4NH3(g)+N2(g)
Given: 2.6mol N2H4

Question

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)=>4NH3(g)+N2(g) 
Given: 2.6mol N2H4

anonymous · Answer

I'm sorry, could you give me an explanation on how to solve this? I am completely lost.

anonymous · Answer

awww i made a misstake i reversed numbers... sorry...
3 moles of N2H4 give you 4 moles of NH3 ->
3 * n(N2H4) = 4 * n(NH3) 
and from there its math

anonymous · Answer

Okay, yeah that had me really confused at first. I understand it now, thank you!

anonymous · Answer

no problem and sorry for misstake, rushing... theres a lesson: dont rush! :)

anonymous · Answer

Thank you for taking the time to explain it to me!