Question

AP CALCULUS BC
Solve for x:
3/(x+3) _< 2/(x-2)
(the sign means smaller than or equal to)

I found (-infinity, -3) U (2, 12]
Is that correct?

Answer 1

so \(x\ne2 \text{, and }x\ne-3\).
then\[ 3\left( x-2 \right) \le 2\left( x+3 \right) \Rightarrow 3\left( x-2 \right)-2\left( x+3 \right) \le 0 \]\[\Rightarrow x-12\le 0 \Rightarrow x \le 12 \Rightarrow \left(-\infty , -3\right) \cup \left(-3, 2\right)\cup \left( 2, 12 \right) \]

Answer 2

you're right, the middle doesn't work.

Answer 3

yeah the middle interval goes -/- which is positive

Answer 4

glad i got the right answer, thanks!

Answer 5

great job!!!