Question

Can you help me solve this problem? (you'll find the problem down below)

Answer 1

Can you put it in to equation

Answer 2

There is a button to the left of draw click on it. It is called equation. You can write out your problem using that so that everyone understands what you are asking for.

Answer 3

well we need to simplify first and take the gcf

Answer 4

\[1/3(x+6)^{-2/3}(2x-3)^2+4(x+6)^{1/3}(2x-3)\] Okay this is the problem...here is what I did...

Answer 5

\[(x+6)^{2/3}(2x-3)[1/3(2x-3)+4(x+6)]\] .......

Answer 6

I then simplified what's in the brackets...

Answer 7

this is what is now in the brackets... \[(14/3+23) ......(14x+69)\]

Answer 8

so now I think I can bring the one with the negative exponent down... \[(2x-3)(14x+69) all divided by (x+6)^{2/3} \]

Answer 9

I don't know what to do next :((((((((

Answer 10

@dumbcow @kohai @mathmath333 I really need you help guys!

Answer 11

wait let me see

Answer 12

thx :)

Answer 13

are we just simplifying or solving?
there is no = sign

Answer 14

\(\Large\tt \color{black}{\dfrac{(x+6)^{\frac{-2}{3}}(2x-3)^2}{3}+4(x+6)^{\frac{1}{3}}}\)

\(\Large\tt \color{black}{=\dfrac{(2x-3)^2}{3(x+6)^{\frac{2}{3}}}+4(x+6)^{\frac{1}{3}}}\)

\(\Large\tt \color{black}{=\dfrac{(2x-3)^2+12(x+6)^{\frac{1+2}{3}}}{3(x+6)^{\frac{2}{3}}}}\)

\(\Large\tt \color{black}{=\dfrac{4x^2-12x+9+12(x+6)}{3(x+6)^{\frac{2}{3}}}}\)

\(\Large\tt \color{black}{=\dfrac{4x^2+81}{3(x+6)^{\frac{2}{3}}}}\)

Answer 15

tell me if there is typo

Answer 16

I think a factor of (2x-3) is missing from the second part:
\[
\Large\tt \color{black}{\dfrac{(x+6)^{\frac{-2}{3}}(2x-3)^2}{3}+4(x+6)^{\frac{1}{3}}}(2x-3)
\]

Answer 17

lol, his drawing i saw in it it was completely missing

Answer 18

no worries at least the part i choose is correct with the missing part @superhelp101 u can look and see the method i worked i try out

Answer 19

\[\large
\frac{(x+6)^{-2/3}(2x-3)^2}{3} + 4(x+6)^{1/3}(2x-3) = \\ \large
\frac{(2x-3)^2}{3(x+6)^{2/3}} + 4(x+6)^{1/3}(2x-3) = \\ \large
\frac{(2x-3)^2+12(x+6)(2x-3)}{3(x+6)^{2/3}} = \\ \large
\frac{4x^2-12x+9+12(2x^2-3x+12x-18)}{3(x+6)^{2/3}} = \\ \large
\frac{4x^2-12x+9+24x^2+108x-216}{3(x+6)^{2/3}} = \\ \large
\frac{28x^2+96x-207}{3(x+6)^{2/3}} =
\frac{(2x-3)(14x+69)}{3(x+6)^{2/3}}
\]

Answer 20

lol I met all of you amazing users when I was new here! And I didn't help and people fanned me.. lol
And now I see all of you guys have also increased your SS since then too. The good old memories. lol