Find: (f(x+c)-f(x))/c If f(x) = 2x^3-5x
can you evaluate f(x+c) if given f(x)=2x^3-5x hint: just replace the old input x wherever you see with the new input (x+c)
@freckles how would you incorporate c if we aren't given a value?
example: if f(x)=x^2 then f(x+c)=(x+c)^2
wherever you see x you replace it with (x+c)
if f(x)=5-x+x^2 then f(x+c)=5-(x+c)+(x+c)^2
so if f(x)=2x^3-5x then f(x+c)=?
once you find f(c+h) we can plug into difference quotient when you are ready for that
@freckles 2(x+c)^3-5(x+c) ?
great! \[\frac{f(x+c)-f(c)}{h}=\frac{[2(x+c)^3-5(x+c)]-[2c^3-5c]}{h}\] now this is the part where we multiply everything out on the top and see if anything cancels in the top
oops that h down there is suppose to be a c by the way
and i read your problem wrong f(c) is f(x) lol
Okay that's what I thought lol!
\[\frac{f(x+c)-f(x)}{c}=\frac{2(x+c)^3-5(x+c)]-[2x^3-5x]}{c}\]
now we still need to multiply stuff out on the top and see if anything cancels on the top
if i was multipying out (x+c)^3 i would refer to my handy dandy pascal's triangle
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