Question

A NaOH solution is standardized against benzoic acid. if a 385.2 mg sample of benzoic acid requires 33.96 ml of NaOH to reach the end point, what is the concentration of the NaOH ?

Answer 1

if we assume that you dilute that 385,2 mg of benzoic acid in 100 ml of water and then titrate with NaOH and spend 33,96 ml of NaOH then i got that concentration is ~ 0,1 M (0,0928...)

first you calculate number of moles of benzoic acid
n=m/M
then you calculate concentration of benzoic acid with asumption that you dilute it in 100 ml
c=n/V
then you use
c1V1 = c2V2
and thats it...