x2/6>7/6 how do i make the variable alone???
@iambatman batman help please
\[\large x ^{\frac{ 2 }{ 6 }}>\frac{ 7 }{ 6 }\] first thing is this what you meant?
yes
Ok well remember 2/6 = 1/3, do you agree?
yep
\(x^{2/6}\) and not \(\dfrac{x^2}{6}\)? Kind of weird for teacher to give you a problem with non-simplified fraction.
wait um i think it would be x>14/36 right?
Ok, so when you deal with such questions, don't be afraid of the sign! Treat it as if it were an = sign, just with some restrictions and what not, so for now we'll just treat as an equal sign as there is no restriction we have to follow (for now). \[x ^{\frac{ 1 }{ 3 }} > \frac{ 7 }{ 6 } \] so how do we cancel 1/3 in the exponent? By cubing both sides. \[x > \left( \frac{ 7 }{ 6 } \right)^3\]
Can you finish it off?
@geerky42 the original problem was 1/3x-1/2>2/3
Mhm
wait i thought to cancel 1.3 you multiply it by 3?
\[\dfrac{1}{3}x-\dfrac{1}{2}>\dfrac{2}{3}\]?
1/3*
Can you draw or use latex for your original problem, kind of confusing.
yes @geerky42
Oh ok so how did you get \[x^{2/6}\]
i made all the numbers with the same numerator.
Or did I just imagine it wrong?
i turned the problem to \[2/6 x-3/4>4/6\]
Oh, then you are on right track @chucho78 You are stuck at \(\dfrac{2}{6}x>\dfrac{7}{6}\) To isolate x, start by multiplying both sides by 6. then divide both sides by 2
Ok that makes sense I thought it was the exponent..
You need to specify these things and also not say yes when I write it out wrong :P
thought you where using it as a fraction my bad.
Np, so yeah multiply both sides by 6/2
2/6*7/6 thats where im stuck @.@
o ok
but how would i multiply the right side?
Multipling both sides would get you \(x>\dfrac{7}{6}\cdot\dfrac{6}{2}\)
You can cancel 6 out.
Thats the confusing part!
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