53.0 mL of a 1.50 M solution is diluted to a total volume of 268 mL. A 134-mL portion of that solution is diluted by adding 123 mL of water. What is the final concentration? Assume the volumes are additive.

Plz help :D

Question

53.0 mL of a 1.50 M solution is diluted to a total volume of 268 mL. A 134-mL portion of that solution is diluted by adding 123 mL of water. What is the final concentration? Assume the volumes are additive. 

Plz help :D

cuanchi · Answer

use the following formula
V1xC1=V2xC2

V1= initial volume
C1= initial concentration
V2= final volume
C2=  Final concentration

anonymous · Answer

oh so 
but it confusing how im given 3 volume in the eqaution

anonymous · Answer

oooops dont mean to sound rude with the so 
typo

anonymous · Answer

:)

cuanchi · Answer

no, you have two steps

cuanchi · Answer

first calculate the concentration of the first dilution, then with that concentration and the 134ml will be your C1V1.
Your V2 is going to be addition of 134+123mL

anonymous · Answer

c1=1,5M
V1=53 ml
V2=268 ml

c1v1=c2v2

c3=c2? you calculate it from upper equation
v3=134 ml
v4=134+123 ml
c4=?

c3v3=c4v4

anonymous · Answer

so 

1.50 * 123ml  = x + 257
is this the corect set up

anonymous · Answer

instead of x 
i mean c2

anonymous · Answer