Determine whether or not the function f:ZxZ->Z is onto, if f((m,n))=|n|. @Mathematics The answer says it i snot onto but i dont get how!
Is f(n)=|n| surjective from the integers to the integers?
Ant other words will we get all the integers as outputs?
or you can graph it |dw:1411948933550:dw| look where the outputs are and aren't
there is a lot integers that do not get hit
what conclusion can you draw from this?
The answer to this question gives is that it is not onto. I wanna knwo the explanation that why is it not onto?
the question is just this much!
so i take it from that you have no idea what i'm talking about
no i didnt get what you are asking
for f:A->B to be surgective all the numbers in B must get hit
surjective *
yes
we have a function that is defined from the integers to the integers by f(x)=|x| but there is no way we can any of the negative integers as output therefore it isn't surjective from the integers to the integers
it would be surjective from the integers to the positive integers
or even the nonnegative integers
|dw:1411949285848:dw| none of those integers i just circled get hit in your function
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