Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Determine whether or not the function f:ZxZ->Z is onto, if f((m,n))=|n|. @Mathematics The answer says it i snot onto but i dont get how!

OpenStudy (freckles):

Is f(n)=|n| surjective from the integers to the integers?

OpenStudy (freckles):

Ant other words will we get all the integers as outputs?

OpenStudy (freckles):

or you can graph it |dw:1411948933550:dw| look where the outputs are and aren't

OpenStudy (freckles):

there is a lot integers that do not get hit

OpenStudy (freckles):

what conclusion can you draw from this?

OpenStudy (anonymous):

The answer to this question gives is that it is not onto. I wanna knwo the explanation that why is it not onto?

OpenStudy (anonymous):

the question is just this much!

OpenStudy (freckles):

so i take it from that you have no idea what i'm talking about

OpenStudy (anonymous):

no i didnt get what you are asking

OpenStudy (freckles):

for f:A->B to be surgective all the numbers in B must get hit

OpenStudy (freckles):

surjective *

OpenStudy (anonymous):

yes

OpenStudy (freckles):

we have a function that is defined from the integers to the integers by f(x)=|x| but there is no way we can any of the negative integers as output therefore it isn't surjective from the integers to the integers

OpenStudy (freckles):

it would be surjective from the integers to the positive integers

OpenStudy (freckles):

or even the nonnegative integers

OpenStudy (freckles):

|dw:1411949285848:dw| none of those integers i just circled get hit in your function

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!