Question

Solve for w.

Answer 1

\[\frac{ (w+1) }{ (w-1) }(-1)=\frac{ (z+i) }{ (z-i) }(-i)\]

Answer 2

I is the complex number.

Answer 3

I.e (i is the square root of -1.)

Answer 4

sleek-feathered one U FKED

Answer 5

@zepdrix , @ganeshie8 , @Zarkon .

Answer 6

@nincompoop

Answer 7

@tkhunny

Answer 8

I feel like this should be simple but I cannot do it for some reason.

Answer 9

I dislike typing in the math so I'll just tell you the steps if that's alright :)

So, start by multiplying in the -1 and the -i.

Next, cross multiply to get everything in the numerator

Put all the terms with w in the left and everything else on the right

Factor out the w and then divide by what you factored it out of.

Congrats! You now have it in the correct form. :D

Answer 10

Okay but I still don't get the right answer.

Answer 11

\[w=\frac{ i(1-z) }{ (1+z) }\]

Answer 12

But I can't get there.

Answer 13

I've got: \[w = \frac{ 1-zi+i-z }{ z-i+1-zi }\]
Which can simplify to \[w = \frac{ (1-z)(1+i) }{ (1-i)(1+z) }\]
It's possible i've done something wrong though....

Answer 14

Nope I got that too.

Answer 15

Recall i is a complex number though. I don't really know how to go from there though...

Answer 16

the LCD is (w - 1)(z-i) but I'll do this in 2 parts

divide by -i
multiply the right hand side, RHS by (z + 1)/(z + 1)
remember i^2 = -1 and simplify
for the LHS, multiply by (w + 1)/(w + 1 ) *-i/-i and simplify

Answer 17

Yep I did that. Here. I'll show you my work.

Answer 18

Mind you I'm in electrical engineering so I use j not i.

Answer 19

Give me a sec.

Answer 20

ok i'll also go through the steps

Answer 21

http://oi59.tinypic.com/15rhyqg.jpg

Answer 22

Multiplying by the complex conjugate will make it even worse.

Answer 23

wait I wrote that wrong on the left you don't have i you have one

on the right I have (z^2 + 2 z i -1)/(z - 1)(z + 1)

Answer 24

Well I didn't expand anything.

Answer 25

But I could.

Answer 26

Got it. Thanks anyways.