Question

a car accelerates uniformly from rest to a speed of 23.7 m/s in 6.5. find the distance the car travels during this time?

Answer 1

where a= acceleration, v= final velocity, u=initial velocity, and d=distance:
v=23.7m/s
u=0

first we need to find acceleration:
a=(v-u)/t
a=(23.7)/6.5s
a=3.6461538 m/s2

then using the formula
d=ut+1/2at^2, we can find the distance:
d=1/2(3.6461538)(42.25)
d=154.04999805