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OpenStudy (anonymous):
Please help! Medal and fan will be awarded :) How many O atoms are there in 2.25g of sodium hydrogen carbonate(NaHCO3)?
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OpenStudy (anonymous):
I basically have: 2.25gNaHCO3/1 * 6.02 x 10^23/1 mole NaHCO3 * 48.0gO/1 mole * 1mole/84.0gNaHCO3 = 7.74 x 10^23
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