Question

question written better in the convo.

is {2} an element of {3,2,1}

1022 {s| s=2^n-2,n element N}

3004 {x| x= 3n+1, n element N}

Answer 1

is \[{2} \in {3,2,1} ? 1022 {s| s=2^n-2,n \in N} ? 3004 {x| x=3n+1, n \in N} \] ?

Answer 2

Is 2 present in {3, 2, 1} ?

Answer 3

yes.. so it is an element?

Answer 4

Yes.

Answer 5

For the next one, try various integer values in \(2^n-2\) and see if any of them give 1022.

Answer 6

sorry but im lost in tht

Answer 7

{s| s=2^n-2,n element N}
n is a natural number (belongs to set N).
That means n = 1, 2, 3, 4, ......
n = 1, s = 2^1 - 2 = 0
n = 2, s = 2^2 - 2 = 2
n = 3, s = 2^3 - 2 = 6
n = 4, s = 2^4 - 2 = 14
....

So instead of saying the set is: {0, 2, 6, 14, .......} the set is expressed by a formula:
{s| s=2^n-2,n element N}.

So keep trying higher n values to see if 1022 is an element of the set.

Answer 8

ooh ok let me try

Answer 9

Don't have to try in sequence. You can skip a few and if it exceeds 1022, step down a little bit.

Answer 10

2^10 -2

Answer 11

Yes, when n = 10, it gives 1022 and therefore 1022 is an element of the set.

Answer 12

so it is an element?

Answer 13

Yes. How about the last one?

Answer 14

it is an element..... 3x1001+1

Answer 15

1 more quest please

Answer 16

are they all \[\subset or are there \subseteq\]

Answer 17

not sure what the question is.

Answer 18

ok are they all subsets or are they proper subsets

Answer 19

If it is about set notations then: http://www.purplemath.com/modules/setnotn.htm

Answer 20

http://it.edgecombe.edu/homepage/killorant/MAT140/Module1/Subsets.pdf

Answer 21

ok so they are all subsets because in a proper subset .. there is at least one elemnt of A that is not in B

Answer 22

@aum

Answer 23

Sorry, the notification system on this site has not been working properly lately and I did not know until now you had posted a reply.

{2} and {3, 2, 1}
The first set is completely contained in the second set AND the first set is NOT equal to the second set. Therefore, it is a proper subset.

Same answer for the other two as well if you consider {1022} as one set and {s| s=2^n-2,n element N} as the other set. The first set is completely contained in the second set and the two sets are not equal. Therefore, it is a proper subset.

{3004} is a proper subset of {x| x= 3n+1, n element N}