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When the polynomial mx^3-3x^2+nx+2 is divided by x+3, the reminder is -1. When it is divided by x-2, the reminder is -4. What are the values of m and n?
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let p(x) = mx^3-3x^2+nx+2
according to the remainder theorem, if you divide p(x) by x-k, then p(k) is the remainder
when "mx^3-3x^2+nx+2 is divided by x+3, the reminder is -1" so p(-3) = -1 because x+3 is in the form x-(-3) and k = -3
so plug x = -3 into mx^3-3x^2+nx+2 and set it equal to -1 mx^3-3x^2+nx+2 m(-3)^3-3(-3)^2+n(-3)+2 = -1 -27m - 27 - 3n + 2 = -1 that's one equation you can work with to solve for m and n
to find the other, plug x = 2 into mx^3-3x^2+nx+2 and set it equal to -4
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