Question

6x^(3/11)-42=0

Answer 1

well rewrite it as

\[6x^{\frac{3}{11}} = 42\]

divide both sides by 6

\[x^{\frac{3}{11}} = 7\]

so raise both sides of the equation to the 11th power

then take the cube root of both sides to find the value of x

Answer 2

it says I can only write it as a fraction and not a decimal. I got 7.73 but I don't know how to get a fraction

Answer 3

well its

\[x^3 = 7^{11}\]

now take the cube root

\[x = \sqrt[3]{7^{11}} = 7^{\frac{11}{3}}\]