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Mathematics 15 Online
OpenStudy (anonymous):

Factor: x(x-3)^3 -28(x-3)^2

OpenStudy (campbell_st):

well removing the common factor you get \[(x - 3)^2 [ x(x - 3) - 28]\] which becomes \[(x - 3)^2[x^2 - 3x - 28]\] the quadratic inside the square brackets can be factored. hope it helps

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