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Mathematics 12 Online
OpenStudy (anonymous):

I really need help with a l'Hospital's rule problem, please!

OpenStudy (anonymous):

What is the limit as x is approaching 0 from the right of (-xlnx)

OpenStudy (aum):

\[ \lim_{x \rightarrow 0^+}-x\ln(x) = -\lim_{x \rightarrow 0^+}\frac{\ln(x)}{1/x} = ? \]

OpenStudy (aum):

Apply L'H rule now because it is of the form infinity / infinity.

OpenStudy (anonymous):

How did you get it in that form?

OpenStudy (aum):

x can be written as \(\frac{1}{1/x}\)

OpenStudy (anonymous):

Got it. Thank you! Can I ask you one more question?

OpenStudy (aum):

go ahead.

OpenStudy (anonymous):

How would I find the limit as x approached 0+ of x^(1/x)?

OpenStudy (aum):

Let y = x^(1/x) Take natural log on both sides: ln(y) = 1/x * ln(x) Now take the limit. Whatever limit you find, y = e^(that limit)

OpenStudy (anonymous):

Thank you so much!!

OpenStudy (aum):

You are welcome.

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