Financial algebra help seriously needed!!
A rare bacterial culture is being grown in a lab. As the days progress, the cells multiply and grow. After 1 day, there is only 1 cell. After 2 days, there are 9 cells. After 3 days, there are 20 cells. After 4 days, there are 34 cells. Which recursive equation represents the pattern?
w(1) = 1 w(n) = w(n-1) + n^2 w(2) = w(1)+2^2 = 5 . . . w(4) = w(3)+4^2 = 30 So an = asub(n-1) +n^2
Thank you but that's not an option?? here are my options:
b
Could you explain that please? Recursive problems are very confusing to me and I'd really like to know how to do it in the future.
turst your gut ok
That doesn't really explain anything?
i dk about explining that
How can you answer it if you can't explain how you figured it out??
this is the series with changing differences 1 9 20 34aa 8 11 14 ------->first difference 8 3 3 --------> second difference 3 \(\large\tt \color{black}{S=a+(n-1)d+\dfrac{(n-1)(n-2)c}{2}}\) \(\large\tt \color{black}{S=1+(n-1)8+\dfrac{(n-1)(n-2)3}{2}}\)
Okay so what do I do after that? Because that isnt one of my options
its the 4th option which is correct
\(\large\tt \color{black}{a_2=a_1+(3\times2+2)}\) \(\large\tt \color{black}{a_2=1+(6+2)}\) \(\large\tt \color{black}{a_2=9}\)
Thank you so much!!
welcome
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