Determine all values of x, (if any) at which the graph of the function has a horizontal tangent. Y(x)=x^3+12x^2+8

Question

campbell_st · Answer

find the 1st derivative... set to zero and then solve for x. 

this will give the point(s) where the tangent is horizontal. 

to find the equation of the tangents, substitute the x values into the original
equation to get the ordered pairs... 

the equations will be the y values from the ordered pairs

anonymous · Answer

so you get 0 and -8?

campbell_st · Answer

that's correct... they are the points...