Use the definition of the derivative to find f'(x)
if f(x) = 2x / (x=4)
Does this mean first principles?
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myininaya (myininaya):
So you are finding the derivative of f(x)=2x at x=4?
myininaya (myininaya):
\[f'(x)=\lim_{h \rightarrow 0}\frac{f(x+h)-f(x)}{h}\]
this definition of derivative
OpenStudy (anonymous):
no
i'm just finding the derivative using first principles can you help me with that?
myininaya (myininaya):
so if f(x) isn't 2x then what is f(x)?
myininaya (myininaya):
was f(x) suppose to be 2x/(x+4) or 2x/(x-4) instead of it being 2x ?
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OpenStudy (anonymous):
+4
myininaya (myininaya):
2x/(x+4) ?
OpenStudy (anonymous):
yes
myininaya (myininaya):
well if f(x)=2x/(x+4)
do you know how to find f(x+h)?
OpenStudy (anonymous):
just plug it in
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myininaya (myininaya):
yep where the x is
OpenStudy (anonymous):
yes but i can't get the real derivative. can you show me the steps? i know the answer is 8/(x+4)^2
myininaya (myininaya):
\[f'(x)=\lim_{h \rightarrow 0}\frac{\frac{2(x+h)}{x+h+4}-\frac{2x}{x+4}}{h}\]
combine top fractions there
it is easy if you just use the drunken smiley face method :)
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