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OpenStudy (anonymous):
OpenStudy (anonymous):
There is a removable discontinuity at x = 3.
There is a non-removable discontinuity at x = 3.
The function is continuous for all real numbers.
myininaya (myininaya):
Well if we had f(x)=(x^2-9)/(x-3)
this is not continuous at x=3
but if we wrote f(x)=(x-3)(x+3)/(x-3)
then we could cancel the x-3's
and we would have f(x)=x+3
so you can then say the discontinuity is removable at x=3
because we just removed it but canceling the x-3's out
myininaya (myininaya):
can you do in your problem?
OpenStudy (anonymous):
yes, it would be A (:
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myininaya (myininaya):
well not exactly
myininaya (myininaya):
can you simplify your fraction?
myininaya (myininaya):
or reduce it is another way to say simplify in this case
OpenStudy (anonymous):
yes, factor then cancel
myininaya (myininaya):
x^2+9 cannot be factored
therefore you cannot get rid of the x-3 on bottom
therefore you cannot remove the discontinuity at x=3
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myininaya (myininaya):
well x^2+9 cannot be factored just over the reals anyways
myininaya (myininaya):
x^2+9=(x-3i)(x+3i)
OpenStudy (anonymous):
ohhh so it's B, my bad i got confused
myininaya (myininaya):
yes
do you understand your answer though?
OpenStudy (anonymous):
yes, you explained it extremely well
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