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Mathematics 15 Online
OpenStudy (anonymous):

calc help!

OpenStudy (anonymous):

OpenStudy (anonymous):

There is a removable discontinuity at x = 3. There is a non-removable discontinuity at x = 3. The function is continuous for all real numbers.

myininaya (myininaya):

Well if we had f(x)=(x^2-9)/(x-3) this is not continuous at x=3 but if we wrote f(x)=(x-3)(x+3)/(x-3) then we could cancel the x-3's and we would have f(x)=x+3 so you can then say the discontinuity is removable at x=3 because we just removed it but canceling the x-3's out

myininaya (myininaya):

can you do in your problem?

OpenStudy (anonymous):

yes, it would be A (:

myininaya (myininaya):

well not exactly

myininaya (myininaya):

can you simplify your fraction?

myininaya (myininaya):

or reduce it is another way to say simplify in this case

OpenStudy (anonymous):

yes, factor then cancel

myininaya (myininaya):

x^2+9 cannot be factored therefore you cannot get rid of the x-3 on bottom therefore you cannot remove the discontinuity at x=3

myininaya (myininaya):

well x^2+9 cannot be factored just over the reals anyways

myininaya (myininaya):

x^2+9=(x-3i)(x+3i)

OpenStudy (anonymous):

ohhh so it's B, my bad i got confused

myininaya (myininaya):

yes do you understand your answer though?

OpenStudy (anonymous):

yes, you explained it extremely well

myininaya (myininaya):

thanks :)

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