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Mathematics 18 Online
OpenStudy (anonymous):

how do you find the zeros in functions

OpenStudy (anonymous):

\[\frac{ 5(x+2 }{ 3(x-1) (x+7}\]

OpenStudy (anonymous):

@phi

OpenStudy (phi):

a fraction is 0 if its "top" is zero (as long as the bottom is not zero at the same time)

OpenStudy (anonymous):

i dont get it??

OpenStudy (anonymous):

so does the top need to equal to zero, as long as the bottom isnt zero too??

OpenStudy (phi):

you have \[ f(x) = \frac{ 5(x+2) }{ 3(x-1) (x+7)} \] that will be zero if the numerator is 0.

OpenStudy (phi):

example: 0/2 = 0 0/anything = 0 (except 0/0 which is not defined)

OpenStudy (phi):

so to answer your question you should find what x value makes (x+2) zero.

OpenStudy (anonymous):

oh ok thank you're very helpful

OpenStudy (phi):

in other words, you could write down 5(x+2) = 0 divide both side by 5 x+2 = 0/5 x+ 2 = 0 add -2 to both sides x= -2 that would make the top zero, so x=-2 is a "zero of your function"

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