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how do you find the zeros in functions
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\[\frac{ 5(x+2 }{ 3(x-1) (x+7}\]
@phi
a fraction is 0 if its "top" is zero (as long as the bottom is not zero at the same time)
i dont get it??
so does the top need to equal to zero, as long as the bottom isnt zero too??
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you have \[ f(x) = \frac{ 5(x+2) }{ 3(x-1) (x+7)} \] that will be zero if the numerator is 0.
example: 0/2 = 0 0/anything = 0 (except 0/0 which is not defined)
so to answer your question you should find what x value makes (x+2) zero.
oh ok thank you're very helpful
in other words, you could write down 5(x+2) = 0 divide both side by 5 x+2 = 0/5 x+ 2 = 0 add -2 to both sides x= -2 that would make the top zero, so x=-2 is a "zero of your function"
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