A block, initially at rest on a friction-free horizontal plane, is acted on by a horizontal force of 25 N. If during 4.0 seconds the block travels 40.0 m, what is its mass?

Question

abhisar · Answer

Hello @dray71837 ,
Welcome to Openstudy !

abhisar · Answer

Using the equation,
$\sf s=ut+\frac{1}{2}at^2$
where,
s=distance
u=initial velocity
a=acceleration and t=time

We can calculate the value of acceleration as follows.

40=0.5*a*16
=>a=5 m/$\sf s^2$

$\sf \because$ Force=acceleration*Mass

$\sf \therefore Mass=\frac{Force}{acceleration}=\frac{25}{5}=5Kg$

anonymous · Answer

Thank you so much! @Abhisar