Question

x^2-7x+10>0

Answer 1

find the zeros first
that is, solve
\[x^2-7x+10=0\] which should not be too hard because this one factors
let me know what you get and we can go from there, it will take one step

Answer 2

7 and 10 it multiplies to 70 and you could factor it with both 10 and 7

Answer 3

you don't have 70, you have 10
think of two numbers whose product is 10

Answer 4

5 and 2 then

Answer 5

yes, that will work, so long as they both are negative, since the "middle term" is \(-7x\)
that means it factors as
\[(x-5)(x-2)=0\] and the zeros are in fact \(2\) and \(5\)

Answer 6

now you want to know where it is positive, not where it is zero
but that is almost the same question
the graph of the quadratic is a parabola that faces up
it is negative between the zeros and positive outside of them

Answer 7

oo ok thank you

Answer 8

you could say \(x<2\) or \(x>5\) or in interval notation
\[(-\infty, 2)\cup (5,\infty)\]

Answer 9

yw