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Differentiate the function
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\[y=\sqrt{x}(x-4)\]
you can multiply out and get \[\large y=x^{\frac{3}{2}}-4x\] then use the all mighty power rule
you got that or no?
so i put 3/2 in front of x and subtract one from the exponent
zactly
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the exponent would be 1/2 correct?
yes
so this is what I got \[y=\frac{ 3 }{ 2 }x ^{\frac{ 1 }{ 2 }}- 4\]
yes
which you could also write as \[y'=\frac{3}{2}\sqrt{x}-4\] if you like
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the hardest part of calc one is adding and subtracting fractions
this answer was no correct because it locked me out of the question making it wrong...
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