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Mathematics 14 Online
OpenStudy (love_to_love_you):

Help?? Will give medal, fan, and write testimony.

OpenStudy (love_to_love_you):

Answer what you can, please show your work.

OpenStudy (love_to_love_you):

@ganeshie8

OpenStudy (love_to_love_you):

@satellite73

OpenStudy (love_to_love_you):

@amistre64

OpenStudy (love_to_love_you):

@jim_thompson5910

OpenStudy (love_to_love_you):

@nincompoop

OpenStudy (love_to_love_you):

@iambatman

OpenStudy (love_to_love_you):

@myininaya

OpenStudy (love_to_love_you):

@aum

OpenStudy (amistre64):

thats quite a lot, can you narrow it down to any one in particular?

OpenStudy (love_to_love_you):

I don't need you to answer all of them, but really just answer any that catch your eye, or that you can do.

OpenStudy (amistre64):

i can do all of them, but me giving you an answer is not going to help you much in my opinion. they even have a small review before a set of questions. if i dont know what you need help sorting out, then i dont know what a good tutoring path to take.

OpenStudy (love_to_love_you):

Okay, basically, I need numbers 3-55 all odd. I have been sick, and have a horrible teacher, and my book isn't working. So I really have no other options than this and it is making me go crazy.

OpenStudy (love_to_love_you):

Why don't we start with 3 and 5. I don't know how to do that.

OpenStudy (amistre64):

tell me your thought on #3

OpenStudy (amistre64):

its just an application of the example that they did for you after all

OpenStudy (love_to_love_you):

Yes it is a function.

OpenStudy (amistre64):

can you tell me why thats your choice?

OpenStudy (love_to_love_you):

Because none of them share the same x coordinate?

OpenStudy (amistre64):

well, thats a good observation, but not quite accurate. if a point was doubled then we would have a smae x coord, but also a same y coord with it becuase its the same point. if 2 different points have the same x part, then its not a function

OpenStudy (love_to_love_you):

Oh

OpenStudy (amistre64):

#5 has to have an assumption, we have to assume that any 2 or more points that are above/below one another share the same x value, but differ in ys

OpenStudy (amistre64):

are there any points that we can assume are above/below another?

OpenStudy (love_to_love_you):

wait so on #3 why is it a function?

OpenStudy (amistre64):

#3 is a function since for any given x value, there is only 1 y value to associate with it

OpenStudy (amistre64):

since all the x parts are difference values to start with then its safe to say that no x value has more than 1 y value associated with it

OpenStudy (amistre64):

*are different values ....

OpenStudy (love_to_love_you):

Oh I see now.

OpenStudy (amistre64):

how about #5?

OpenStudy (love_to_love_you):

On #5 we could assume that there are points beneath the bottom points on the graph shown?

OpenStudy (amistre64):

of all the points we see, we need to assume that if one point is above another, that they share a common x value. otherwise the question has no single correct solution.

OpenStudy (amistre64):

can you visually tell the difference between x=.000001 and x = .000002 ??

OpenStudy (love_to_love_you):

So it is not a function?

OpenStudy (amistre64):

why can we assume its not a function?

OpenStudy (love_to_love_you):

I don't think so

OpenStudy (love_to_love_you):

Because the points share the same x

OpenStudy (amistre64):

which points? how would you define them as best you can?

OpenStudy (love_to_love_you):

errr..

OpenStudy (love_to_love_you):

I honestly, don't know.

OpenStudy (amistre64):

well, either some points look like they fit on a vertical line, or they dont

OpenStudy (love_to_love_you):

Some of them do look like they fit on a line.

OpenStudy (amistre64):

assume we are able to draw a perfectly vertical line up and down thru any x value, are there any points that look like they would get hit by this line?

OpenStudy (love_to_love_you):

1.5 and -3.5

OpenStudy (love_to_love_you):

right?

OpenStudy (amistre64):

at x about -1.5 i see 2 points that seem to be in a line top to bottom

OpenStudy (love_to_love_you):

Yeah

OpenStudy (amistre64):

then if we ask what is the value of y at x = -1.5 .... we get 2 different answers. so its not a function

OpenStudy (amistre64):

what are you thoughts about #7?

OpenStudy (love_to_love_you):

still working on that

OpenStudy (love_to_love_you):

so far I have this f(-2) = -x +4 f(-2) = 2 + 4 @amistre64

OpenStudy (love_to_love_you):

whoops

OpenStudy (love_to_love_you):

f(-2) = -x +4 f(-2) = 2 + 4 f(-2) = 6 f(-0.5) = -x + 4 f(-0.5) = 0.5 + 4 f(-0.5) = 4.5

OpenStudy (amistre64):

i would have prefered -(-2), then simplify to 2 but thats fine

OpenStudy (amistre64):

if you can mentally work the double negative, more power to you ... but it can sometimes come back to bite you

OpenStudy (love_to_love_you):

How so?

OpenStudy (love_to_love_you):

f(3) = -x + 4 f(3) = -3 +4 f(3) = 1

OpenStudy (love_to_love_you):

is all of that right?

OpenStudy (amistre64):

thats all fine

OpenStudy (love_to_love_you):

I don't know how to do #9

OpenStudy (amistre64):

what is a direct variation?

OpenStudy (love_to_love_you):

when two quantities increase and decrease at the same rate

OpenStudy (amistre64):

good, so if we have the setup y = kx, then when y gets big, x gets big and k stays the same

OpenStudy (love_to_love_you):

11 does use direct variation but I don't think 9 does

OpenStudy (amistre64):

all we need is 2 points of reference to determine k

OpenStudy (love_to_love_you):

I don't know much about it. So....

OpenStudy (amistre64):

yeah, 2/3 is not equal to 1/4 so its not a direct constant variation

OpenStudy (amistre64):

1/1 = 2/2 = 5/5 gives us a direct variation, can you think of a y=kx that fits it?

OpenStudy (love_to_love_you):

No...

OpenStudy (love_to_love_you):

How would I find one that does?

OpenStudy (love_to_love_you):

oh is the y=kx the rule?

OpenStudy (amistre64):

if the ratio, the fraction, of x/y is the same for all point x,y then we have a direct variation ideally tho thats backwards but works anyways. the equation you want to determine is some y = kx for a constant value of k: hence k = y/x for any point x,y

OpenStudy (love_to_love_you):

is it the rule?

OpenStudy (amistre64):

if you want to call it a rule, sure

OpenStudy (love_to_love_you):

Okay, is is y=x?

OpenStudy (amistre64):

yep

OpenStudy (amistre64):

thats for #11 right?

OpenStudy (love_to_love_you):

yeah

OpenStudy (amistre64):

#9 has no equality to determine so its just not workable by the instructions

OpenStudy (love_to_love_you):

so the answer is literally no

OpenStudy (amistre64):

correct

OpenStudy (amistre64):

now #13 and #15 are the last ones for me

OpenStudy (amistre64):

tell me what you think its asking for

OpenStudy (love_to_love_you):

Alright, and thank you so much for your help. I really do appreciate it.

OpenStudy (amistre64):

yw

OpenStudy (love_to_love_you):

uh are they asking for the k in y=kx?

OpenStudy (amistre64):

yep, so define k = y/x for the given y and x, then determine the new y when x=-.3

OpenStudy (love_to_love_you):

so k= -0.5/2?

OpenStudy (amistre64):

another way to see it is: \[k=\frac{y_1}{x_1}=\frac{y_2}{-.3}\] \[y_2=\frac{-.3~y_1}{x_1}\]

OpenStudy (amistre64):

y2 = -.3(2/3) ------- .2 y2 = -3/2 (2/3) = -1

OpenStudy (love_to_love_you):

whoops I accidentally was doing 12.

OpenStudy (amistre64):

lol, 12 is fine for practice as well

OpenStudy (love_to_love_you):

So the COV is -1?

OpenStudy (amistre64):

no, COV is y1/x1 = (2/3)/.2 = 20/6 = 10/3

OpenStudy (amistre64):

the value of y2 is -1

OpenStudy (amistre64):

-1/-.3 = 10/3

OpenStudy (love_to_love_you):

Ohh.

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