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OpenStudy (love_to_love_you):
Answer what you can, please show your work.
OpenStudy (love_to_love_you):
@ganeshie8
OpenStudy (love_to_love_you):
@satellite73
OpenStudy (love_to_love_you):
@amistre64
OpenStudy (love_to_love_you):
@jim_thompson5910
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OpenStudy (love_to_love_you):
@nincompoop
OpenStudy (love_to_love_you):
@iambatman
OpenStudy (love_to_love_you):
@myininaya
OpenStudy (love_to_love_you):
@aum
OpenStudy (amistre64):
thats quite a lot, can you narrow it down to any one in particular?
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OpenStudy (love_to_love_you):
I don't need you to answer all of them, but really just answer any that catch your eye, or that you can do.
OpenStudy (amistre64):
i can do all of them, but me giving you an answer is not going to help you much in my opinion. they even have a small review before a set of questions.
if i dont know what you need help sorting out, then i dont know what a good tutoring path to take.
OpenStudy (love_to_love_you):
Okay, basically, I need numbers 3-55 all odd. I have been sick, and have a horrible teacher, and my book isn't working. So I really have no other options than this and it is making me go crazy.
OpenStudy (love_to_love_you):
Why don't we start with 3 and 5. I don't know how to do that.
OpenStudy (amistre64):
tell me your thought on #3
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OpenStudy (amistre64):
its just an application of the example that they did for you after all
OpenStudy (love_to_love_you):
Yes it is a function.
OpenStudy (amistre64):
can you tell me why thats your choice?
OpenStudy (love_to_love_you):
Because none of them share the same x coordinate?
OpenStudy (amistre64):
well, thats a good observation, but not quite accurate. if a point was doubled then we would have a smae x coord, but also a same y coord with it becuase its the same point.
if 2 different points have the same x part, then its not a function
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OpenStudy (love_to_love_you):
Oh
OpenStudy (amistre64):
#5 has to have an assumption, we have to assume that any 2 or more points that are above/below one another share the same x value, but differ in ys
OpenStudy (amistre64):
are there any points that we can assume are above/below another?
OpenStudy (love_to_love_you):
wait so on #3 why is it a function?
OpenStudy (amistre64):
#3 is a function since for any given x value, there is only 1 y value to associate with it
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OpenStudy (amistre64):
since all the x parts are difference values to start with then its safe to say that no x value has more than 1 y value associated with it
OpenStudy (amistre64):
*are different values ....
OpenStudy (love_to_love_you):
Oh I see now.
OpenStudy (amistre64):
how about #5?
OpenStudy (love_to_love_you):
On #5 we could assume that there are points beneath the bottom points on the graph shown?
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OpenStudy (amistre64):
of all the points we see, we need to assume that if one point is above another, that they share a common x value. otherwise the question has no single correct solution.
OpenStudy (amistre64):
can you visually tell the difference between x=.000001 and x = .000002 ??
OpenStudy (love_to_love_you):
So it is not a function?
OpenStudy (amistre64):
why can we assume its not a function?
OpenStudy (love_to_love_you):
I don't think so
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OpenStudy (love_to_love_you):
Because the points share the same x
OpenStudy (amistre64):
which points? how would you define them as best you can?
OpenStudy (love_to_love_you):
errr..
OpenStudy (love_to_love_you):
I honestly, don't know.
OpenStudy (amistre64):
well, either some points look like they fit on a vertical line, or they dont
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OpenStudy (love_to_love_you):
Some of them do look like they fit on a line.
OpenStudy (amistre64):
assume we are able to draw a perfectly vertical line up and down thru any x value, are there any points that look like they would get hit by this line?
OpenStudy (love_to_love_you):
1.5 and -3.5
OpenStudy (love_to_love_you):
right?
OpenStudy (amistre64):
at x about -1.5 i see 2 points that seem to be in a line top to bottom
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OpenStudy (love_to_love_you):
Yeah
OpenStudy (amistre64):
then if we ask what is the value of y at x = -1.5 .... we get 2 different answers. so its not a function
OpenStudy (amistre64):
what are you thoughts about #7?
OpenStudy (love_to_love_you):
still working on that
OpenStudy (love_to_love_you):
so far I have this f(-2) = -x +4
f(-2) = 2 + 4
@amistre64
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i would have prefered -(-2), then simplify to 2 but thats fine
OpenStudy (amistre64):
if you can mentally work the double negative, more power to you ... but it can sometimes come back to bite you
OpenStudy (love_to_love_you):
How so?
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OpenStudy (love_to_love_you):
f(3) = -x + 4
f(3) = -3 +4
f(3) = 1
OpenStudy (love_to_love_you):
is all of that right?
OpenStudy (amistre64):
thats all fine
OpenStudy (love_to_love_you):
I don't know how to do #9
OpenStudy (amistre64):
what is a direct variation?
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OpenStudy (love_to_love_you):
when two quantities increase and decrease at the same rate
OpenStudy (amistre64):
good, so if we have the setup
y = kx, then when y gets big, x gets big and k stays the same
OpenStudy (love_to_love_you):
11 does use direct variation but I don't think 9 does
OpenStudy (amistre64):
all we need is 2 points of reference to determine k
OpenStudy (love_to_love_you):
I don't know much about it. So....
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OpenStudy (amistre64):
yeah, 2/3 is not equal to 1/4 so its not a direct constant variation
OpenStudy (amistre64):
1/1 = 2/2 = 5/5 gives us a direct variation, can you think of a y=kx that fits it?
OpenStudy (love_to_love_you):
No...
OpenStudy (love_to_love_you):
How would I find one that does?
OpenStudy (love_to_love_you):
oh is the y=kx the rule?
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OpenStudy (amistre64):
if the ratio, the fraction, of x/y is the same for all point x,y then we have a direct variation
ideally tho thats backwards but works anyways. the equation you want to determine is some y = kx for a constant value of k: hence k = y/x for any point x,y
OpenStudy (love_to_love_you):
is it the rule?
OpenStudy (amistre64):
if you want to call it a rule, sure
OpenStudy (love_to_love_you):
Okay, is is y=x?
OpenStudy (amistre64):
yep
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OpenStudy (amistre64):
thats for #11 right?
OpenStudy (love_to_love_you):
yeah
OpenStudy (amistre64):
#9 has no equality to determine so its just not workable by the instructions
OpenStudy (love_to_love_you):
so the answer is literally no
OpenStudy (amistre64):
correct
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OpenStudy (amistre64):
now #13 and #15 are the last ones for me
OpenStudy (amistre64):
tell me what you think its asking for
OpenStudy (love_to_love_you):
Alright, and thank you so much for your help. I really do appreciate it.
OpenStudy (amistre64):
yw
OpenStudy (love_to_love_you):
uh are they asking for the k in y=kx?
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OpenStudy (amistre64):
yep, so define k = y/x for the given y and x, then determine the new y when x=-.3
OpenStudy (love_to_love_you):
so k= -0.5/2?
OpenStudy (amistre64):
another way to see it is:
\[k=\frac{y_1}{x_1}=\frac{y_2}{-.3}\]
\[y_2=\frac{-.3~y_1}{x_1}\]
OpenStudy (amistre64):
y2 = -.3(2/3)
-------
.2
y2 = -3/2 (2/3) = -1
OpenStudy (love_to_love_you):
whoops I accidentally was doing 12.
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OpenStudy (amistre64):
lol, 12 is fine for practice as well
OpenStudy (love_to_love_you):
So the COV is -1?
OpenStudy (amistre64):
no, COV is y1/x1 = (2/3)/.2 = 20/6 = 10/3
OpenStudy (amistre64):
the value of y2 is -1
OpenStudy (amistre64):
-1/-.3 = 10/3
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