Let A, B, C, and D be sets. Prove that if if C ⊆ A and D ⊆ B, then C ∩ D ⊆ A ∩ B.
to prove X <= Y in general, you need to show that if x is a member of A then x is a member of B
we want to prove that if C<=D and D<= B , then (C int. D) <= (A int. B)
where I am using ' <= " to mean subset
int. = intersection
to prove X <= Y in general, you need to show that if x is a member of X then x is a member of Y
proof: Does it follow from the fact that C<=A and D<=B that (C int. D) <= (A int. B)? Thats basically what we are going to show. So we are given C<=D and D<=B. Next suppose that x is a member of ( C int. D). This implies x is a member of C and x is a member of D, separately. But this implies x is member of A, and x is a member of B. This implies x is a member of A int. B. Therefore we have shown that (C int. D) <= (A int. B)
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