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sin^2(x)+cosx=2
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"use the pythagorean identity sin^2(x)+cos^2(x)=1"
solve for x?
no solve the equation
can you check the question...as I think there is a typo
there is no typo
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if the question is correct then using sin^2 = 1 - cos^2 you get \[1 - \cos^2(x) + \cos(x) = 2\] or \[\cos^2(x) - \cos(x) + 1 = 0\] which has no real solutions...
now you have a quadratic that can't be solved...
i got the same as @campbell_st
I also got that answer
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the only solutions to this problem lie in the set of complex numbers
wwould you recommend just writing no solution ?
well that's what I would answer
all right thanks
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