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Mathematics 19 Online
OpenStudy (anonymous):

sin^2(x)+cosx=2

OpenStudy (anonymous):

"use the pythagorean identity sin^2(x)+cos^2(x)=1"

OpenStudy (anonymous):

solve for x?

OpenStudy (anonymous):

no solve the equation

OpenStudy (campbell_st):

can you check the question...as I think there is a typo

OpenStudy (anonymous):

there is no typo

OpenStudy (campbell_st):

if the question is correct then using sin^2 = 1 - cos^2 you get \[1 - \cos^2(x) + \cos(x) = 2\] or \[\cos^2(x) - \cos(x) + 1 = 0\] which has no real solutions...

OpenStudy (campbell_st):

now you have a quadratic that can't be solved...

OpenStudy (anonymous):

i got the same as @campbell_st

OpenStudy (anonymous):

http://puu.sh/bUY2C/4e286cb520.png

OpenStudy (anonymous):

I also got that answer

OpenStudy (campbell_st):

the only solutions to this problem lie in the set of complex numbers

OpenStudy (anonymous):

wwould you recommend just writing no solution ?

OpenStudy (campbell_st):

well that's what I would answer

OpenStudy (anonymous):

all right thanks

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