Question

Tutorial:

Mean, Median, Mode, Range.

Answer 1

\(\bf Mean~is~the~average.\)

You add all the numbers and divide by how many numbers there are.

\(\bf Median~is~the~middle~value.\)

You list the numbers in order of least to greatest, and find the middle value.

\(\bf Mode~is~the~number~that~is~repeated~the~most.\)

Find the number that's repeated the most.

\(\bf Range~is~the~difference~between~the~biggest~number~and~the~smallest~number.\)

Subtract the highest term from the smallest term.

\(\bf\color{lime}{Examples:}\)

\(\bf Mean:\)

2, 5, 7, 10, 14, 15, 18

Add all the terms:

\(2 + 5 + 7 + 10 + 14 + 15 + 18 = 71\)

There are 7 numbers total.

Divide: \(71 \div 7 = 10.14\)

So the mean is approximately 10.14.

\(\bf Median:\)

Median can be a little confusing.

If you have an odd number of values, it's easy to spot the middle term:

1, 5, 6, 9, 11

\(\color{lime}{1,5,}\color{red}{6,}\color{blue}{9,11}\)

The middle value is 6, so the median is 6.

However if you have an even number of values, it's a bit different:

2, 3, 5, 6, 7, 9

\(\color{lime}{2,3,}\color{red}{5,6,}\color{blue}{7,9}\)

There seems to be 2 middle numbers.

You have to find the mean of these two numbers to find the real median.

\(5 + 6 = 11\)

\(11 \div 2 = 5.5\)

So the median is 5.5.

\(\bf Mode:\)

5, 5, 6, 6, 6, 9, 9, 10, 14, 15

Here, you can see that 6 is repeated the most, so 6 is the Mode.

There can also be two modes.

If you didn't have those 6's in your values:

5, 5, 9, 9, 10, 14, 15

Then the mode would be 5 AND 9, because they’re both repeated the same number of times, and they’re both repeated the most than any other term.

\(\bf Range:\)

6, 9, 11, 16, 21, 23, 27

Locate the biggest and the smallest numbers:

\(\color{red}6, 9, 11, 16, 21, 23, \color{red}{27}\)

Subtract them:

27 – 6 = 21

So the Range here will be 21.

Note: You always subtract the smaller number from the bigger number. Your answer cannot be a negative.

Answer 2

Please let me know if I did anything wrong..xD

Answer 3

Lol, looks right to me:) But....u gotta see what the *intelligent* has to sayxD!!! Erm...ganeshie

Answer 4

Yes, xD

Answer 5

I made this because I had to explain it so much to other people..now I can just copy & paste the link.

Answer 6

Nice and to the point :) there was a question on mode the other day which I couldn't answer :
```
If mean = median = 12, find the value of mode
```

Maybe this topic can be covered in Tutorial2 :)

Answer 7

Finally!!!!!! Someone gave u a question u couldn't answer!!!! lol!!! Just kiddingxD!!

Answer 8

LOL

Answer 9

Well if your only term was 12..then the mode would also be 12..

Answer 10

how did you do the rainbow numbers?

Answer 11

There's a thing called "LaTeX"

Answer 12

Oh, that's LaTeX.

You can learn it here: http://openstudy.com/study#/updates/52e12f56e4b0942cc9de719e

Answer 13

@ganeshie8

Answer 14

yeah the options are something like that too, let me see if i can pull up that question quick

Answer 15

Okay.

Answer 16

Aha!

0, 0, 0, 24, 24, 24

Mean:

0 + 0 + 0 + 24 + 24 + 24 = 72

72 / 6 = 12

Median:

The middle numbers are 0 and 24.

Find the mean between them:

0 + 24 = 24

24 / 2 = 12.

Mode:

0, 0, 0, 24, 24, 24

Your mode will be 0 AND 24.

@ganeshie8

Answer 17

Also:

12, 12, 12, 12, 12, 12

Mean:

12, 12, 12, 12, 12, 12 = 72

72 / 6 = 12

Median:

Obviously 12.

Mode:

12 is the only term..

Answer 18

10, 11, 12, 13, 14

Mean:

10 + 11 + 12 + 13 + 14 = 60

60 / 5 = 12

Median:

12

Mode:

10, 11, 12, 13, and 14

Answer 19

The answer must be that there are multiple modes.. @ganeshie8

Answer 20

I see... then the mode could be anything is it ?

Answer 21

Well..pretty much. It depends on what values you have in your set.

Answer 22

Gotcha! :D

Answer 23

Great work !
Thanx for sharing

Answer 24

great help thanks i was getting stuck on this

Answer 25

Please add Quartiles to this tutorial. Thanks. @iGreen

Answer 26

This was very helpful, thanks!