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Calculus1 60 Online
OpenStudy (anonymous):

how do you find the implicit derivative of tan(x+y)=y

OpenStudy (lieutenantgeneral):

http://www.sosmath.com/calculus/diff/der05/der05.html

OpenStudy (amistre64):

by using your derivative rules

OpenStudy (jonnyvonny):

All implicit differentiation is that all the 'y's" become y' (y prime). Honestly, you've been doing it since you've taking derivatives when you started i.e. y=2x... y'=2. I sec brb i'll help out. 'less someone else takes my place

OpenStudy (amistre64):

all the ys do not become y's all the ys follow the chain rule: for example: 3y^2 beocmes 6y y'

OpenStudy (amistre64):

doing it all along, id have to almost disagree, weve simply been ignoring the chain rule on x y = 2x y' = 2 x' now x', with respect to x, is dx/dx =1 so this simplifies to: y' =2

OpenStudy (amistre64):

do you recall the derivative rule for tan(u)?

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