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OpenStudy (anonymous):
how do you find the implicit derivative of tan(x+y)=y
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OpenStudy (lieutenantgeneral):
OpenStudy (amistre64):
by using your derivative rules
OpenStudy (jonnyvonny):
All implicit differentiation is that all the 'y's" become y' (y prime). Honestly, you've been doing it since you've taking derivatives when you started i.e. y=2x... y'=2. I sec brb i'll help out. 'less someone else takes my place
OpenStudy (amistre64):
all the ys do not become y's all the ys follow the chain rule: for example: 3y^2 beocmes 6y y'
OpenStudy (amistre64):
doing it all along, id have to almost disagree, weve simply been ignoring the chain rule on x y = 2x y' = 2 x' now x', with respect to x, is dx/dx =1 so this simplifies to: y' =2
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OpenStudy (amistre64):
do you recall the derivative rule for tan(u)?
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