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What volume of 0.135 M HClO4 solution is needed to neutralize 52.00mL of 8.60×10−2 M NaOH?
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Use the Dilution equation and solve for the volume of HClO4 M1V1= M2V2 M1= is the moles per liter of HClO4 = 0.135 V1=is the amount of solution in litres of HClO4 = ? M2= is the moles per liter of NaOH= 8.60x10^-2 V2= is the amount of solution in litres of NaOH= 52.00mL (it's ok if it is in mL bcuz both volumes will be in mL for v1 and v2) 0.135*V1 = ( 8.60x10^-2 mol) *(52.00mL) Solve for V1 which is the volume of HClO4
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