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given Cl2 + 3F2 = 2ClF3, how many grams of ClF3 form from 130.0 grams of Cl2 when F2 is in excess?
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ok first calculate how many moles of Cl2 you have by using: n = m/M and then put that moles in ratio with product (hint: it takes one mole of Cl2 to get 2 moles of ClF3) and from there you get how many moles of product you get and just reverse previously mentioned equation: m = n * M
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