Given the reactant side of the total ionic equation for the neutralization reaction of lithium hydroxide (LiOH) with hydrochloric acid (HCl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow. Li+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→ ? Be sure to include the charges on the ionic species and the physical state of all the reactant and product species.
so you have reaction of neutralization LiOH + HCl -> LiCl + H2O and now you have to meet all conditions writen in task so just copy paste what you have Li+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> LiCl(s) + H2O(l) thats what i would do at the moment
thank you!
The answer was: Li+(aq) + OH-(aq) + H+(aq) + Cl-(aq) --> Li+(aq) +Cl-(aq) +H2O(l)
sorry my misstake due to lack of sleep
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