Question

Determine the value of x : (x,5) (-4,3) slope=-1????

Answer 1

You can use slope formula: \(m = \dfrac{y_2-y_1}{x_2-x_1}\). Plug in these value and solve for x.

Answer 2

https://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/point-slope-form/v/linear-equations-in-point-slope-form

Answer 3

ok so 3-5/-4-x

Answer 4

yeah, now solve for x

Answer 5

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ x}}\quad ,&{\color{blue}{ 5}})\quad &({\color{red}{ -4}}\quad ,&{\color{blue}{ 3}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\implies \cfrac{{\color{blue}{ 3}}-{\color{blue}{ 5}}}{{\color{red}{ -4}}-{\color{red}{ x}}}=1\)

solve for "x"

Answer 6

hmmm actually should be -1 so
\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ x}}\quad ,&{\color{blue}{ 5}})\quad &({\color{red}{ -4}}\quad ,&{\color{blue}{ 3}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\implies \cfrac{{\color{blue}{ 3}}-{\color{blue}{ 5}}}{{\color{red}{ -4}}-{\color{red}{ x}}}=-1\)