Question

Help!!!! Giving Medal!!!

Balance the following equation for the combustion of benzene:
C6H6 (l) + O2 (g) -----> H2O (g) + CO2 (g)

Answer 1

Okay so when I do this i make a chart with the ions seperated and how many are on each side of the arrow. product side/reactant side

Answer 2

So I would make one column like this
C 6
H 6
O 2

Answer 3

So we have 6 C, 6H and 2O on the reactant side (to the left of the arrow) and we have
C 6 1
H 6 2
O 2 3

Answer 4

So we have 1 Carbon, 2H and 3O on the product side.

To balance this we need to get H from 2 to 6.

Answer 5

If we put a 3 infront of H20 we now have 6 H but now we have 5O on the product side and only 2 O on the reactant side.

Answer 6

Ok, i kind of get how to do the chart...so it wouldnt be able to balance?

Answer 7

eventually, one sec i'm seeing if i have the answer now.

Answer 8

K

Answer 9

Okay so after figuring it out I got 2C6H6 + 15o2 ----> 6H2O + 12CO2

Answer 10

If you add them all up in the chart they balance out. I tried seeing if you can make that smaller but you can't without there being odd numbers. Originally I had it balanced with 7.5 in front of the O2 and that balanced out completely but you can't leave that a fraction so just multiply it by 2 and you get 15 and then you have to multiply the product side that has O in it by 2 too so that they equal the same in the chart...if that makes sense..

Answer 11

Yes it does make sense :)
Thanks so much for guiding me through it..now I can do for the rest of my assignment :)

Answer 12

No problem, if any other ones give you trouble just tell me and I'll see what I can do.

Answer 13

Okay thanks :)