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If you had .681 moles of CASO4*2H2O, how many moles of H2O do you have?
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You set this up as a basic dimensional analysis equation. Soo one second I'll write it out
\[.681 mol CaSO _{4} * \frac{ 2molH _{2} 0}{ 1molCaSO _{4} }= your answser\]
So the mols of CaSO4 cancel out and you are left with mols of H2O. The original equation has a 2mol H2O to 1mol CaSO4 so you just multiply what you are given by 2.
Thank you. so would the answer be 1.362 moles of H2O?
Yup! I would round it to 1.36 so you have the same amount of sig figs as the .681
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