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Mathematics 17 Online
OpenStudy (jojokiw3):

Help would be most appreciated.

OpenStudy (jojokiw3):

\[3\sqrt{9 \sqrt[4]{3}}\]

OpenStudy (jojokiw3):

Can I have like, all the steps. o_O

OpenStudy (campbell_st):

rewrite the innermost radical \[9\sqrt[4]{3} = 3^2 \times 3^{\frac{1}{4}} = \] remember multiplying the same base, add the powers...

OpenStudy (anonymous):

My bad... @campbell_st is right i missed the 4 on the square root

OpenStudy (campbell_st):

when you get the answer \[3^{\frac{a}{b}}\] then apply the power of a power rule... which is multiply the powers \[(3^{\frac{a}{b}})^{\frac{1}{3}}\] lastly multiply the answer by \[3^1\] again adding the powers

OpenStudy (jojokiw3):

\[3^{\frac{ 17 }{ 8 }}\]

OpenStudy (aum):

\[\large 3\sqrt{9 \sqrt[4]{3}} ~~\text{ OR }~~ \sqrt[3]{9 \sqrt[4]{3}} \]

OpenStudy (jojokiw3):

First one.

OpenStudy (campbell_st):

that's correct, well done

OpenStudy (jojokiw3):

Thanks. :)

OpenStudy (campbell_st):

so in radical form it's \[\sqrt[8]{3^{17}}\]

OpenStudy (aum):

\[\Large 3^{17/8} = 3^{2+1/8} = 3^2 * 3^{1/8} = 9\sqrt[8]{3} \]

OpenStudy (jojokiw3):

Oh I see. Thank you. :)

OpenStudy (jojokiw3):

I kept forgetting to ADD the powers. xD

OpenStudy (aum):

You are welcome.

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