how do i find the inverse of f(x)=9/11x
\[ f(x) = \frac{9}{11}x ~~ \text{ OR } ~~ f(x) = \frac{9}{11x} \]
Which one of the above is the correct problem?
the second one
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y = 9 / (11x) solve for x: multiply both sides by 1x y * x = 9/11 divide both sides by y: x = 9 / (11y) interchange x and y: y = 9/(11x) Inverse = 9/(11x)
i dont get it...
If you are given a function f(x) and asked to find the inverse, these are the steps: 1. Replace f(x) by y. Here we rewrote f(x)=9/(11x) as y = 9/(11x) 2. Solve for x. Here, x = 9/(11y) 3. Interchange x and y. y = 9/(11x) 4. Replace y with \(f^{-1}(x)\). Therefore the inverse function is: \(\large f^{-1}(x) = \frac{9}{11x}\).
Here the inverse function is same as the original function. This happens whenever the function is symmetrical about the y = x line.
alright, its just that i have to write the question like this:
???
f^-1(x) = ax +b/ cx + d)
\[ \large f^{-1}(x) = \frac{9}{11x} = \frac{0x + 9}{11x + 0} \]a = 0, b = 9, c = 11, d = 0
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