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Mathematics 8 Online
OpenStudy (anonymous):

Select the equation for a graph that is the set of all points in the plane that are equidistant from point F(1/2,0) and line x= -1/2

OpenStudy (anonymous):

I need to know how to do this step by step.

OpenStudy (anonymous):

If you can help me I will give you a medal.

OpenStudy (anonymous):

translate as "find the equation for the parabola with focus \((\frac{1}{2},0)\) and directrix \(x=-\frac{1}{2}\)

OpenStudy (anonymous):

I dont understand?

OpenStudy (anonymous):

that is the definition of a parabola the set of all points equidistant from a given point and a line

OpenStudy (anonymous):

I have a question off topic, but do admins get paid for being on here ALL the time?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

How are you so good at math. Or what makes it were you can help with any question????

OpenStudy (anonymous):

i am old as dirt you got how to do this?

OpenStudy (anonymous):

not a clue

OpenStudy (anonymous):

you know what it looks like?

OpenStudy (anonymous):

sort of

OpenStudy (anonymous):

draw it you need that first, then it will be very very easy

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

|dw:1412218192140:dw|

OpenStudy (anonymous):

I think thats right

OpenStudy (anonymous):

probbaly not though

OpenStudy (anonymous):

\(x=-\frac{1}{2}\) is a vertical line and the point \((\frac{1}{2},0)\) is on the x axis

OpenStudy (anonymous):

|dw:1412218341300:dw|

OpenStudy (anonymous):

I feel like you almost giving me the answer, but I'm feeling like an idiot right now.

OpenStudy (anonymous):

the parabola therefore opens to the right and looks something like this |dw:1412218398988:dw|

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