Question

ok so how do i solve this (t + 1)^3 - 49 (t + 1)

Answer 1

First factor out (t+1)


\[\Large (t + 1)^3 - 49(t + 1)\]


\[\Large (t + 1)((t + 1)^2 - 49)\]


Then you factor \(\large (t + 1)^2 - 49\) using the difference of squares rule


\[\Large (t + 1)((t + 1)^2 - 49)\]


\[\Large (t + 1)((t + 1)^2 - 7^2)\]


\[\Large (t + 1)(t + 1 - 7)(t + 1 + 7)\]


\[\Large (t + 1)(t - 6)(t + 8)\]

Answer 2

ok thank you very much

Answer 3

np