help.
with
still? don't you ever sleep?
more like "i can sleep for a week"
Directions: Type the correct answer in the box. Use numerals instead of words. Consider the equations of the two lines shown below. \[Line 1: y=\frac{ 3 }{ 5 }x+2\] \[Line 2: y=\frac{ 3 }{ 5 }x-1\] Find the distance between the two lines. The distance between line 1 and line 2, rounded to the nearest hundredth, is units.
help? :)
lines are parallel how far from \(-1\) to \(2\) ?
4? -1,0,1,2.
lol no
from \(-1\) to \(2\)is three steps up
like if you were in the basement and walked to the second floor, you would go up three stories
or if you like math, \(2-(-1)=2+1=3\)
when you counted -1,0,1,2. you should not count the -1 it is three steps -1 to 0, 0 to 1, 1 to 2
Ooohh. o_o Woops? :) So the answer is 3, and that does make sense about not counting -1.
well actually no, the answer is not 3, but i think that is what they want you to say that is the vertical distance
"rounded to the nearest hundredth" Sounds like they actually want shortest distance possible between two lines
actually my answer is totally wrong, i don't think you want the vertical distance at all it is a different question
\[d=\frac{|b_2-b_1|}{\sqrt{m^2+1}}\] is what i think you have to compute
If it's up to me, I would create third line, that is perpendicular to both given lines. Then I would find the intersection of line 1 and 3, and intersection of line 2 and 3. Then I would find distance between these points.
so the 3 is right for the numerator, but the denominator should be \[\sqrt{\left(\frac{3}{5}\right)^2+1}\]
I would just trust @satellite73
Whoo 90 SS
nah, i would go with @geerky42 it will just take more time but will be a better understanding
Join our real-time social learning platform and learn together with your friends!