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Mathematics 15 Online
OpenStudy (anonymous):

help.

OpenStudy (anonymous):

with

OpenStudy (anonymous):

still? don't you ever sleep?

geerky42 (geerky42):

OpenStudy (anonymous):

more like "i can sleep for a week"

OpenStudy (anonymous):

Directions: Type the correct answer in the box. Use numerals instead of words. Consider the equations of the two lines shown below. \[Line 1: y=\frac{ 3 }{ 5 }x+2\] \[Line 2: y=\frac{ 3 }{ 5 }x-1\] Find the distance between the two lines. The distance between line 1 and line 2, rounded to the nearest hundredth, is units.

OpenStudy (anonymous):

help? :)

OpenStudy (anonymous):

lines are parallel how far from \(-1\) to \(2\) ?

OpenStudy (anonymous):

4? -1,0,1,2.

OpenStudy (anonymous):

lol no

OpenStudy (anonymous):

from \(-1\) to \(2\)is three steps up

OpenStudy (anonymous):

like if you were in the basement and walked to the second floor, you would go up three stories

OpenStudy (anonymous):

or if you like math, \(2-(-1)=2+1=3\)

OpenStudy (anonymous):

when you counted -1,0,1,2. you should not count the -1 it is three steps -1 to 0, 0 to 1, 1 to 2

OpenStudy (anonymous):

Ooohh. o_o Woops? :) So the answer is 3, and that does make sense about not counting -1.

OpenStudy (anonymous):

well actually no, the answer is not 3, but i think that is what they want you to say that is the vertical distance

geerky42 (geerky42):

"rounded to the nearest hundredth" Sounds like they actually want shortest distance possible between two lines

OpenStudy (anonymous):

actually my answer is totally wrong, i don't think you want the vertical distance at all it is a different question

OpenStudy (anonymous):

\[d=\frac{|b_2-b_1|}{\sqrt{m^2+1}}\] is what i think you have to compute

geerky42 (geerky42):

If it's up to me, I would create third line, that is perpendicular to both given lines. Then I would find the intersection of line 1 and 3, and intersection of line 2 and 3. Then I would find distance between these points.

OpenStudy (anonymous):

so the 3 is right for the numerator, but the denominator should be \[\sqrt{\left(\frac{3}{5}\right)^2+1}\]

geerky42 (geerky42):

I would just trust @satellite73

geerky42 (geerky42):

Whoo 90 SS

OpenStudy (anonymous):

nah, i would go with @geerky42 it will just take more time but will be a better understanding

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