Mathematics
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OpenStudy (anonymous):
(a) Find the equation of the tangent line to
f(x) = x3 − 3x2 + 2x − 2
at
x = 2.
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OpenStudy (anonymous):
what does y= ?
OpenStudy (anonymous):
im confused on what im supposed to do?
i understand to find the tangent line i must find the derivative. right?
OpenStudy (gorv):
find derivative
OpenStudy (gorv):
that will give you slope
OpenStudy (gorv):
f ' (x)=3x^2-6x+2
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OpenStudy (anonymous):
\[f \prime (x) = 3x ^{2}-6x+2\]
OpenStudy (gorv):
at x=2
find its value ???
OpenStudy (gorv):
f ' (2) =????
replace x by 2 here
OpenStudy (anonymous):
2
OpenStudy (anonymous):
\[f \prime (2) = 2\]
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OpenStudy (anonymous):
\[f \prime (2) = 3(2)^{2}-6(2)+2 = 12-12+2 = 2\]
OpenStudy (anonymous):
right?
OpenStudy (gorv):
now this is slope of the tangent
OpenStudy (anonymous):
so what is Y= ?
OpenStudy (anonymous):
does* y= ?
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OpenStudy (gorv):
now we have x=2 we need valur of y so that we can find the point from which it will pass
OpenStudy (anonymous):
find f(2)
OpenStudy (gorv):
that is m=slope
OpenStudy (gorv):
y=mx+c
OpenStudy (anonymous):
so y-y1 = m(x-x1) ?
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OpenStudy (anonymous):
or y - f(a)=m(x-a)
OpenStudy (gorv):
so to find y put x=2 in f(x) equation which is in start
OpenStudy (gorv):
yeah but we need y1
OpenStudy (anonymous):
yea but you need you actual function value at 2 so just plug 2 into the original
OpenStudy (anonymous):
oh yeah
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OpenStudy (gorv):
which we will get when we calculate f(2)
OpenStudy (gorv):
you got it ??
OpenStudy (anonymous):
but we dont have m do we?
oh yeah m=2, and x=2
OpenStudy (anonymous):
yea m = f'(x) derivative is your slope
OpenStudy (anonymous):
y=-2
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OpenStudy (anonymous):
then plug in my factors and get y?
OpenStudy (anonymous):
so using the format of y - y1 = m(x - x1) you get?
OpenStudy (anonymous):
\[y-(-2)= 2(x-2)\]
OpenStudy (anonymous):
yes that is you tangent line equation
OpenStudy (anonymous):
y=2x-6
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OpenStudy (gorv):
f(x) = x3 − 3x2 + 2x − 2
find f(2) here
OpenStudy (gorv):
f(x)=x3-3x2=2x-2
find f(2) from here
OpenStudy (anonymous):
she has that it is -2
OpenStudy (anonymous):
so my steps are=
1. find m by finding the derivative
2. find y by plugging x into f(x)
3. set my equation y-y1=m(x-x1) and plug in my factors
OpenStudy (anonymous):
correct
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OpenStudy (gorv):
yeppp
OpenStudy (gorv):
you got the concept
OpenStudy (anonymous):
to find M i plug x=2 into f1(x) right?
OpenStudy (anonymous):
that will give me the slope at x=2 ?
OpenStudy (anonymous):
yes you plut your x-value given into your derivative formula
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OpenStudy (anonymous):
plug*
OpenStudy (gorv):
no no no
slope we calculated by derivative
OpenStudy (anonymous):
yyaaayyy i think i'm finally getting the hang of this lol
OpenStudy (gorv):
we have to find value of y corresponding to x=2
OpenStudy (anonymous):
yea F(prime)X = derivative
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OpenStudy (gorv):
f(x) give value of y corrresponding to x
OpenStudy (anonymous):
basic format of these problems if your given that x equals a value
1. find f'(x)
2. find f'(a)
3.find f(a)
4. plug values into y - y1 = m(x - x1)
OpenStudy (gorv):
y=f(2)=2^3-3*2^2+2*2-2
OpenStudy (gorv):
y=f(2)=8-12+4-2=-2
so tangent pass through (2,-2)
OpenStudy (gorv):
and slope = 2
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OpenStudy (gorv):
y-(-2)=2(x-2)
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
A solution and plot is attached. The calculations and plot are from Mathematica 9.