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plz tell me the integration of sin(x)/3+sin(2x)
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\[\int\limits \frac{ sinx }{ 3} *dx +\int\limits 2sinx*cosx *dx\]
integration of sin = -cos
-cosx/3
sin2x=2sinx*cosx it is an identity
so now we have 2sinx*cosx
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let sinx=t differentiate cosx*dx=dt
\[\int\limits2*sinx*cosx*dx=2* \int\limits t*dt\]
arpit can u solve it now
yes i can solve it thxxx Gorv
welcm:)
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Notice that the integral of sin(2x) is -(1/2)cos(2x), to see this without subbing just take the derivative of the result, and see how I just did the opposite for the chain rule. (its a good trick)
It is easy to undo the chain rule, if only constants are involved
@Arpit97 you should give @gorv a medal for helping you understand.
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