Given f(x) = 2x + 3 and ( f o g)(x) = –2x^2 + 13. find g(x)?
well, 2g + 3 = -2x^2 +13, solve for g
why did the x in f(x) become g?
because of the notation: (fog)(x) = f(g(x)) so we simply let all x in f be the value of g
(fog) = f(g) since f(x) = 2x + 3, when x=g we have: f(g) = 2g + 3
ohhh ok, but what if its the other way around?
it's just the same? the x in g(x) will become f?
you mean g(f) is equal to some function?
if we want to determine (gof) then yes we let all x in g be equal to f
I solved the problem and got g(x) = –x^2 + 5 . I was just wondering if you could pretend to not know the value of f(x) and solve for the f(x)
that's -x^2+5
if we were given g(x) = -x^2 + 5, and (fog)(x) = -2x^2 + 13, and find f(x) ?
yes
since we have no f to place g into, it gets trickier and not as precise. we know we need a -2x^2 so multiplying by -2 is a good step to take -2g = -2x^2 + 10 we know we want a +13 so we need to add in 3 -2g + 3 = -2x^2 + 13 and we have a construction that matches now so we we let all g in f be equal to x to determine f(x)
and i seem to have forgotten the we had a -x^2 up from to start with ... so the steps i thought of arent accurate for that one
ohh you're a math genius
sometimes, other times im just a math idiot :)
thanks I understood it
good luck ;)
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