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A solution with a pH of 9 has a [OH-] concentration of A. 1.0 × 10–14 mol/L. B. 1.0 × 10–9 mol/L. C. 1.0 × 10–5 mol/L. D. 1.0 × 10–7 mol/L.
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@JFraser
pH=-log[H+] Kw= [H+][OH-]=10^-14
use the relationship between pH and pOH, and the mathematic relationship that turns pOH into concentration\[pH + pOH = 14\]and\[10^{-pOH} = [OH^{-1}]\]
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