Question

Find the axis of symmetry for:

2x^2-4x+2

Isn't it something like:

x=1?

Answer 1

This is a vertical parabola that opens upward.
So the axis of symmetry will be a vertical line of the form x = constant that passes through the vertex of the parabola. What is the x-coordinate of the vertex of the parabola?

Answer 2

for an equation

\[y = ax^2 + bx + c\]

the axis of symmetry is

\[b = \frac{-b}{2a}\]

you have a = 2 and b = -4

so substitute and find it

Answer 3

oops should read

\[x = \frac{-b}{2a}\]

Answer 4

For the vertex I got (1,0)

Answer 5

That's why I said x=1

Answer 6

well that's another valid method... putting the equation in vertex form

y=2(x - 1)^2

there are lots of methods... both show the line of symmetry is x = 1