Find the axis of symmetry for:

2x^2-4x+2

Isn't it something like:

x=1?

Question

Find the axis of symmetry for:

2x^2-4x+2

Isn't it something like:

x=1?

aum · Answer

This is a vertical parabola that opens upward.
So the axis of symmetry will be a vertical line of the form x = constant that passes through the vertex of the parabola.  What is the x-coordinate of the vertex of the parabola?

campbell_st · Answer

for an equation 

$$y = ax^2 + bx + c$$

the axis of symmetry is 

$$b = \frac{-b}{2a}$$

you have a = 2 and b = -4

so substitute and find it

campbell_st · Answer

oops should read 

$$x = \frac{-b}{2a}$$

anonymous · Answer

For the vertex I got (1,0)

anonymous · Answer

That's why I said x=1

campbell_st · Answer

well that's another valid method... putting the equation in vertex form 

y=2(x - 1)^2

there are lots of methods... both show the line of symmetry is x = 1