Question

starting at a height of 0 feet, a ball is thrown upwards with an initial velocity of 64ft/sec. The ball's height after t seconds is s(t)=-16t^2+64t. Find the average velocity from t=2 to t=5.

Answer 1

To find the velocity, you would need to take the derivative of the function, which would be: s'(t) = -32t + 64

Then you plug in t=2 and t=5 into the derivative function.

Average velocity means change in position over change in time. So to find the average velocity this is what you would need to do:

\[\frac{ s'(5) - s'(2) }{ s(5) - s(2) }\]

Answer 2

Thank you

Answer 3

Your welcome.