Question

Write a function that satisfies these conditions:
a) deleted point at x =3
b) vertical asymptote at x = 0
c) lim x-> +- infinity = -1

Answer 1

i know how to make equation with a and b, but how do i satisfy c?

Answer 2

To satisfy c, you need the limit of the coefficients of x to approach -1.

Answer 3

so for a i can use (x-3) for numerator and denominator and for b i can use (x) for denominator giving me

(x-3)
-----
x(x-3)

and then so i can multiply numerator by -x so that it satisfies c?

Answer 4

No, that will result in a line with two removable discontinuities.

Answer 5

but wouldn't multplying by -x give me

-x^2+3x
---------
x^2-3x

so then -x^2/x^2 is -1?

Answer 6

@amistre64 please, help.

Answer 7

@amistre64 can you please help me

Answer 8

@TheLukeskywalker2

Answer 9

Write a function that satisfies these conditions:
a) deleted point at x =3

assuming this is a hole:

(x-3)
-----
(x-3)





b) vertical asymptote at x = 0

well, put an x multipier on bottom then

(x-3)
------
x(x-3)


as is, this goes to 0 as x to +- inf



c) lim x-> +- infinity = -1

well, since we limit at zero, what would you suggest would move a function down by 1?