Got a Calculus Question: You shoot a rifle at an angle of 26 degrees. The bullet leaves your rifle at a height of 6 feet and a speed of 863 feet per second. It hits the ground after seconds at a distance of feet.
this assumes you know the parametric formulas to apply
aaand that I do not know.
x(t) = vo cos(a) t y(t) = -16t^2 + vo sin(a) t + ho
so the 6 feet I will use in the y(t) equation, right?
yep, also the initial velocity and the angle
so x(t)=863(cos(26))
the equation for y is therefore a quadratic in t, solve for t that zeros it out when we know when height = 0 we know the time it takes to use in the x equation
y(t)=-16t^2+863(sin(26)(t))+6
so set that equation equal to zero and solve for t?
yep y = 0, solve for t
would that just be the quadratic formula, or is it different because there is a sin in there?
863 sin(26) is just some number, the quad formula is fine
I plugged that in and got 41.139611725, but I got that it was wrong(this is for y).
0 = 16t^2+863t sin(26)+6 this works out to be about 23.66
therefore the distance traveled along the x axis is about 863(23.66) cos(26)
I did 23.66 and that didn't get the answer either.
41 is what wee get when we use 26 radians
can you take a screen shot of the problem?
ok so I got 23.660492935, and it isn't taking that either.
Correction, that was the answer for the x(seconds after hitting the ground)
it may be asking for so many decimals, or a round or something
yes, time it takes to hit the ground, 23.66
I got 775.659261956 for the distance, not taking that.
how far it went, assuming a horizontal distance is being asked for ... x(t) = vo t cos(a)
make sure your calculator is reading degrees, and not radians
ya, I did cos26 degrees times 863.
you didnt multiply it by the time we found did you
No I didn't, haha, just realized that.
That did it, thank you so much!
youre welcome
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