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OpenStudy (anonymous):
Given the equation y=3x, find average rate of change of y from x1=0 to x2=8
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OpenStudy (anonymous):
I know the avg rate of change is (y2-y1)/(x2-x1)
OpenStudy (anonymous):
i got y1=0 and y2=64
OpenStudy (anonymous):
and as far as 64/8
OpenStudy (anonymous):
I have a few problems like this so I dont know what to do for them
jimthompson5910 (jim_thompson5910):
how did you get y2 = 64?
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jimthompson5910 (jim_thompson5910):
I'm getting
y = 3x
y = 3*8
y = 24
so y2 = 24 when x2 = 8
OpenStudy (anonymous):
oh that makes more sense. webwork's examples are confusing
jimthompson5910 (jim_thompson5910):
hmm, well anyways, what new final answer do you get?
OpenStudy (anonymous):
WebWork said to do it as (x2)^2 so I squared 8.
I got 3
jimthompson5910 (jim_thompson5910):
isn't the original equation y = 3x and not y = x^2 ?
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OpenStudy (anonymous):
yea
jimthompson5910 (jim_thompson5910):
just a bad typo it seems
jimthompson5910 (jim_thompson5910):
yeah the avg rate of change is 3
jimthompson5910 (jim_thompson5910):
for any linear equation, the avg rate of change is the slope of the line
jimthompson5910 (jim_thompson5910):
you'll see that avg rate of change visually corresponds to the slope of the secant line
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