how do I write the molecular equation for the neutralization of H2SO3 by KOH?

Question

darkigloo · Answer

@ganeshie8 @aaronq

aaronq · Answer

$H_2SO_3$ loses both protons, these react with $OH^-$ and form water, the rest of the ions just recombine because of the charges.

aaronq · Answer

$SO_3^{2-}$ combines with $K^+$

aaronq · Answer

in other words, in the equation, it would look as if you made another compound, the salt of potassium sulfite

aaronq · Answer

yep just make sure you balance the equation

darkigloo · Answer

why is it H2O? How do H2 and OH make H2O?

aaronq · Answer

because $H_2SO_3$ is 2 $H^+$ and $SO_3^{2-}$. It's not $H_2$

aaronq · Answer

$H^+ +OH^-\rightarrow H_2O$

darkigloo · Answer

im confused..sorry.

aaronq · Answer

let me draw it maybe it'll be clearer

aaronq · Answer

|dw:1412383188340:dw|

aaronq · Answer

KOH, in water, exists as $K^+$ and $OH^-$

$OH^-$ comes and steals an $H^+$ from $H_2SO_3$

The electrons that made the bond from Hydrogen to Oxygen go to the oxygen atom

|dw:1412383320628:dw|


the oxygen atom acquires a negative charge and the K^+ ion is attracted to it because of the opposite charges
|dw:1412383394826:dw|